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0=5x^2+7x-4
We move all terms to the left:
0-(5x^2+7x-4)=0
We add all the numbers together, and all the variables
-(5x^2+7x-4)=0
We get rid of parentheses
-5x^2-7x+4=0
a = -5; b = -7; c = +4;
Δ = b2-4ac
Δ = -72-4·(-5)·4
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{129}}{2*-5}=\frac{7-\sqrt{129}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{129}}{2*-5}=\frac{7+\sqrt{129}}{-10} $
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